Empirical Formula Calculator
Empirical Formula is evaluated from% or Mass - Element 1, Atomic Mass - Element 1 and% or Mass - Element 2. The calculation reports Moles Element 1, Moles Element 2 and Moles Element 3.
Results
About the Empirical Formula Calculator
The calculator uses a multi formula configuration. Each reported value is read as a direct evaluation of the stored rules with the declared field formats and units.
Formula basis:
Step 1: mol_i =%_i / atomic_mass_i (assume 100g sample)
Step 2: ratio_i = mol_i / min(all mol values)
Step 5: n = actual molar mass / empirical formula mass
Molecular formula = empirical x n
Interpret the outputs in the order shown by the result fields. Optional inputs affect only the outputs that depend on those variables.
Formula & How It Works
The calculation applies the following relations exactly as recorded in the metadata: Step 1: mol_i =%_i / atomic_mass_i (assume 100g sample) Step 2: ratio_i = mol_i / min(all mol values) Step 5: n = actual molar mass / empirical formula mass Molecular formula = empirical x n Each output field is produced by substituting the supplied inputs into the relevant relation and then applying the declared rounding or text format.
Worked Examples
Example 1: Glucose Empirical Formula — C₆H₁₂O₆ → CH₂O
Inputs
With% or Mass - Element 1 = 40, Atomic Mass - Element 1 = 12.011,% or Mass - Element 2 = 6.71 and Atomic Mass - Element 2 = 1.008 as the stated inputs, the result is Moles Element 1 = 3.3303 mol, Moles Element 2 = 6.6567 mol and Moles Element 3 = 3.3308 mol. Each value corresponds to the declared output fields.
Example 2: Aspirin Empirical Formula — C₉H₈O₄
Inputs
With% or Mass - Element 1 = 60, Atomic Mass - Element 1 = 12.011,% or Mass - Element 2 = 4.44 and Atomic Mass - Element 2 = 1.008 as the stated inputs, the result is Moles Element 1 = 4.9954 mol, Moles Element 2 = 4.4048 mol and Moles Element 3 = 2.2226 mol. Each value corresponds to the declared output fields.
Example 3: Iron Oxide Empirical Formula
Inputs
With% or Mass - Element 1 = 69.94, Atomic Mass - Element 1 = 55.845,% or Mass - Element 2 = 30.06 and Atomic Mass - Element 2 = 15.999 as the stated inputs, the result is Moles Element 1 = 1.2524 mol, Moles Element 2 = 1.8789 mol and Ratio Element 1 = 1. Each value corresponds to the declared output fields.
Example 4: Unknown Organic Compound
Inputs
With% or Mass - Element 1 = 52.14, Atomic Mass - Element 1 = 12.011,% or Mass - Element 2 = 13.13 and Atomic Mass - Element 2 = 1.008 as the stated inputs, the result is Moles Element 1 = 4.341 mol, Moles Element 2 = 13.0258 mol and Moles Element 3 = 2.1708 mol. Each value corresponds to the declared output fields.
Common Use Cases
- Find empirical formula from elemental percent composition
- Determine simplest formula from mass data
- Calculate molecular formula given molar mass and empirical formula