Stoichiometry Calculator

Stoichiometry is evaluated from Given Mass, Molar Mass of Given and Stoichiometric Coefficient. The calculation reports Moles of Given, Moles of Wanted and Mass of Wanted.

Results

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About the Stoichiometry Calculator

Stoichiometry is treated here as a quantitative relation between Given Mass, Molar Mass of Given, Stoichiometric Coefficient and Stoichiometric Coefficient and Moles of Given, Moles of Wanted, Mass of Wanted and Mole Ratio.

The calculator uses a multi formula configuration. Each reported value is read as a direct evaluation of the stored rules with the declared field formats and units.

Formula basis:
mol(given) = mass(given) / M(given)
mol(wanted) = mol(given) x [coeff(wanted) / coeff(given)]
mass(wanted) = mol(wanted) x M(wanted)
Mole ratio = coeff(wanted) / coeff(given)

Interpret the outputs in the order shown by the result fields. Optional inputs affect only the outputs that depend on those variables.

Formula & How It Works

The calculation applies the following relations exactly as recorded in the metadata:

mol(given) = mass(given) / M(given)
mol(wanted) = mol(given) x [coeff(wanted) / coeff(given)]
mass(wanted) = mol(wanted) x M(wanted)
Mole ratio = coeff(wanted) / coeff(given)

Each output field is produced by substituting the supplied inputs into the relevant relation and then applying the declared rounding or text format.

Worked Examples

Example 1: Combustion of Propane (BBQ Grill)

Inputs

given_mass: 44 given_molar_mass: 44.1 given_coeff: 1 wanted_coeff: 3 wanted_molar_mass: 44.01
Moles of Given: 0.9977 mol. Moles of Wanted: 2.9932 mol. Mass of Wanted: 131.7306 g. Mole Ratio: 3 mol/mol

With Given Mass = 44, Molar Mass of Given = 44.1, Stoichiometric Coefficient = 1 and Stoichiometric Coefficient = 3 as the stated inputs, the result is Moles of Given = 0.9977 mol, Moles of Wanted = 2.9932 mol and Mass of Wanted = 131.7306 g. Each value corresponds to the declared output fields.

Example 2: Antacid Chemistry — NaHCO₃ Neutralizing HCl

Inputs

given_mass: 4.2 given_molar_mass: 84.01 given_coeff: 1 wanted_coeff: 1 wanted_molar_mass: 44.01
Moles of Given: 0.05 mol. Moles of Wanted: 0.05 mol. Mass of Wanted: 2.2002 g. Mole Ratio: 1 mol/mol

With Given Mass = 4.2, Molar Mass of Given = 84.01, Stoichiometric Coefficient = 1 and Stoichiometric Coefficient = 1 as the stated inputs, the result is Moles of Given = 0.05 mol, Moles of Wanted = 0.05 mol and Mass of Wanted = 2.2002 g. Each value corresponds to the declared output fields.

Example 3: Haber Process — Ammonia Synthesis (Fertilizer)

Inputs

given_mass: 280 given_molar_mass: 28.02 given_coeff: 1 wanted_coeff: 2 wanted_molar_mass: 17.03
Moles of Given: 9.9929 mol. Moles of Wanted: 19.9857 mol. Mass of Wanted: 340.3569 g. Mole Ratio: 2 mol/mol

With Given Mass = 280, Molar Mass of Given = 28.02, Stoichiometric Coefficient = 1 and Stoichiometric Coefficient = 2 as the stated inputs, the result is Moles of Given = 9.9929 mol, Moles of Wanted = 19.9857 mol and Mass of Wanted = 340.3569 g. Each value corresponds to the declared output fields.

Example 4: Bleach Decomposition Safety

Inputs

given_mass: 74.5 given_molar_mass: 74.44 given_coeff: 2 wanted_coeff: 2 wanted_molar_mass: 58.44
Moles of Given: 1.0008 mol. Moles of Wanted: 1.0008 mol. Mass of Wanted: 58.4871 g. Mole Ratio: 1 mol/mol

With Given Mass = 74.5, Molar Mass of Given = 74.44, Stoichiometric Coefficient = 2 and Stoichiometric Coefficient = 2 as the stated inputs, the result is Moles of Given = 1.0008 mol, Moles of Wanted = 1.0008 mol and Mass of Wanted = 58.4871 g. Each value corresponds to the declared output fields.

Common Use Cases

  • Convert grams of reactant to grams of product
  • Calculate moles using mole ratios from balanced equations
  • Determine theoretical yield of a chemical reaction