Concrete Volume Calculator

Concrete Volume is evaluated from Length, Width and Thickness / Depth. The calculation reports Volume, Volume and Volume with Overage.

Results

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About the Concrete Volume Calculator

Concrete Volume is treated here as a quantitative relation between Length, Width, Thickness / Depth and Waste / Overage and Volume, Volume, Volume with Overage and Volume with Overage.

The calculator uses a multi formula configuration. Each reported value is read as a direct evaluation of the stored rules with the declared field formats and units.

Formula basis:
Volume (ft^3) = L(ft) x W(ft) x D(in) / 12
Volume (yd^3) = V(ft^3) / 27
With overage: V x (1 + waste%/100)
Weight approximately V(yd^3) x 4,050 lb/yd^3

Interpret the outputs in the order shown by the result fields. Optional inputs affect only the outputs that depend on those variables.

Formula & How It Works

The calculation applies the following relations exactly as recorded in the metadata:

Volume (ft^3) = L(ft) x W(ft) x D(in) / 12
Volume (yd^3) = V(ft^3) / 27
With overage: V x (1 + waste%/100)
Weight approximately V(yd^3) x 4,050 lb/yd^3

Each output field is produced by substituting the supplied inputs into the relevant relation and then applying the declared rounding or text format.

Worked Examples

Example 1: Residential Driveway Slab

Inputs

length_ft: 40 width_ft: 16 depth_in: 4 waste_pct: 10
Volume: 213.33 ft^3. Volume: 7.9 yd^3. Volume with Overage: 8.69 yd^3. Volume with Overage: 234.67 ft^3. Approx. Weight: 16 tons

With Length = 40, Width = 16, Thickness / Depth = 4 and Waste / Overage = 10 as the stated inputs, the result is Volume = 213.33 ft^3, Volume = 7.9 yd^3 and Volume with Overage = 8.69 yd^3. Each value corresponds to the declared output fields.

Example 2: Garage Floor

Inputs

length_ft: 24 width_ft: 24 depth_in: 4 waste_pct: 10
Volume: 192 ft^3. Volume: 7.11 yd^3. Volume with Overage: 7.82 yd^3. Volume with Overage: 211.2 ft^3. Approx. Weight: 14.4 tons

With Length = 24, Width = 24, Thickness / Depth = 4 and Waste / Overage = 10 as the stated inputs, the result is Volume = 192 ft^3, Volume = 7.11 yd^3 and Volume with Overage = 7.82 yd^3. Each value corresponds to the declared output fields.

Example 3: Continuous Footing

Inputs

length_ft: 120 width_ft: 1.5 depth_in: 12 waste_pct: 10
Volume: 180 ft^3. Volume: 6.67 yd^3. Volume with Overage: 7.33 yd^3. Volume with Overage: 198 ft^3. Approx. Weight: 13.5 tons

With Length = 120, Width = 1.5, Thickness / Depth = 12 and Waste / Overage = 10 as the stated inputs, the result is Volume = 180 ft^3, Volume = 6.67 yd^3 and Volume with Overage = 7.33 yd^3. Each value corresponds to the declared output fields.

Example 4: Backyard Patio

Inputs

length_ft: 15 width_ft: 20 depth_in: 3.5 waste_pct: 10
Volume: 87.5 ft^3. Volume: 3.24 yd^3. Volume with Overage: 3.56 yd^3. Volume with Overage: 96.25 ft^3. Approx. Weight: 6.6 tons

With Length = 15, Width = 20, Thickness / Depth = 3.5 and Waste / Overage = 10 as the stated inputs, the result is Volume = 87.5 ft^3, Volume = 3.24 yd^3 and Volume with Overage = 3.56 yd^3. Each value corresponds to the declared output fields.

Common Use Cases

  • Calculate cubic yards of concrete for a driveway slab
  • Find concrete volume for a rectangular footing
  • Estimate concrete needed for a basement floor