Buoyancy Calculator
Buoyancy is evaluated from Fluid Density, Submerged Volume and Object Mass. The calculation reports Buoyant Force, Buoyant Force and Mass of Displaced Fluid.
Results
About the Buoyancy Calculator
The calculator uses a multi formula configuration. Each reported value is read as a direct evaluation of the stored rules with the declared field formats and units.
Formula basis:
F = ρ x V x g
F = Buoyant Force (N)
ρ = Fluid density (kg/m^3)
V = Volume of displaced fluid (m^3)
g = 9.80665 m/s^2
Object floats if: F_buoyancy > Weight (m_object x g)
Net force = F_buoyancy - Weight
Interpret the outputs in the order shown by the result fields. Optional inputs affect only the outputs that depend on those variables.
Formula & How It Works
The calculation applies the following relations exactly as recorded in the metadata: F = ρ x V x g F = Buoyant Force (N) ρ = Fluid density (kg/m^3) V = Volume of displaced fluid (m^3) g = 9.80665 m/s^2 Object floats if: F_buoyancy > Weight (m_object x g) Net force = F_buoyancy - Weight Each output field is produced by substituting the supplied inputs into the relevant relation and then applying the declared rounding or text format.
Worked Examples
Example 1: Steel Ship Hull
Inputs
With Fluid Density = 1,025, Submerged Volume = 50,000 and Object Mass = 40,000,000 as the stated inputs, the result is Buoyant Force = 502,590,812.5 N, Buoyant Force = 112,986,937.967 lbf and Mass of Displaced Fluid = 51,250,000 kg. Each value corresponds to the declared output fields.
Example 2: Foam Pool Float
Inputs
With Fluid Density = 1,000, Submerged Volume = 0.02 and Object Mass = 4 as the stated inputs, the result is Buoyant Force = 196.133 N, Buoyant Force = 44.092 lbf and Mass of Displaced Fluid = 20 kg. Each value corresponds to the declared output fields.
Example 3: Submarine Neutral Buoyancy
Inputs
With Fluid Density = 1,025, Submerged Volume = 7,800 and Object Mass = 7,995,000 as the stated inputs, the result is Buoyant Force = 78,404,166.75 N, Buoyant Force = 17,625,962.323 lbf and Mass of Displaced Fluid = 7,995,000 kg. Each value corresponds to the declared output fields.
Example 4: Dock Flotation Barrels
Inputs
With Fluid Density = 1,000, Submerged Volume = 0.208 and Object Mass = 15 as the stated inputs, the result is Buoyant Force = 2,039.783 N, Buoyant Force = 458.562 lbf and Mass of Displaced Fluid = 208 kg. Each value corresponds to the declared output fields.
Common Use Cases
- Determine if a ship design will float
- Calculate buoyant force on a submarine ballast tank
- Find required volume to keep a dock float afloat