Brick & Block Calculator
Brick & Block is evaluated from Material Type, Wall Length and Wall Height. The calculation reports Wall Area, Units Needed and With Waste Factor.
Results
About the Brick & Block Calculator
The calculator uses a multi formula configuration. Each reported value is read as a direct evaluation of the stored rules with the declared field formats and units.
Formula basis:
Units per wall = Wall Area / Unit Face Area (including mortar joints)
Unit face area = (brick length + joint size) x (brick height + joint size)
Standard brick face area: (7.625 + 0.375) x (2.25 + 0.375) = 8 x 2.625 = 21 in^2 = 0.1458 ft^2
→ approximately 6.86 bricks per square foot
CMU face area: (15.625 + 0.375) x (7.625 + 0.375) = 16 x 8 = 128 in^2 = 0.889 ft^2
→ approximately 1.125 blocks per square foot
Wall area = wall length x wall height
Interpret the outputs in the order shown by the result fields. Optional inputs affect only the outputs that depend on those variables.
Formula & How It Works
The calculation applies the following relations exactly as recorded in the metadata: Units per wall = Wall Area / Unit Face Area (including mortar joints) Unit face area = (brick length + joint size) x (brick height + joint size) Standard brick face area: (7.625 + 0.375) x (2.25 + 0.375) = 8 x 2.625 = 21 in^2 = 0.1458 ft^2 → approximately 6.86 bricks per square foot CMU face area: (15.625 + 0.375) x (7.625 + 0.375) = 16 x 8 = 128 in^2 = 0.889 ft^2 → approximately 1.125 blocks per square foot Wall area = wall length x wall height Each output field is produced by substituting the supplied inputs into the relevant relation and then applying the declared rounding or text format.
Worked Examples
Example 1: Garden brick wall: 20 ft × 3 ft, standard brick
Inputs
With Material Type = Standard Brick (3.625 x 2.25 x 7.625 in), Wall Length = 20, Wall Height = 3 and Mortar Joint Size = 0.375 as the stated inputs, the result is Wall Area = 60 ft^2, Units Needed = 412 units and With Waste Factor = 432 units. Each value corresponds to the declared output fields.
Example 2: CMU garage foundation wall: 40 ft × 4 ft
Inputs
With Material Type = Concrete Block CMU (7.625 x 7.625 x 15.625 in), Wall Length = 40, Wall Height = 4 and Mortar Joint Size = 0.375 as the stated inputs, the result is Wall Area = 160 ft^2, Units Needed = 180 units and With Waste Factor = 199 units. Each value corresponds to the declared output fields.
Example 3: Brick fireplace face: 4 ft × 4 ft
Inputs
With Material Type = Standard Brick (3.625 x 2.25 x 7.625 in), Wall Length = 4, Wall Height = 4 and Mortar Joint Size = 0.375 as the stated inputs, the result is Wall Area = 16 ft^2, Units Needed = 110 units and With Waste Factor = 121 units. Each value corresponds to the declared output fields.
Example 4: Retaining wall: 30 ft × 2 ft CMU blocks
Inputs
With Material Type = Concrete Block CMU (7.625 x 7.625 x 15.625 in), Wall Length = 30, Wall Height = 2 and Mortar Joint Size = 0.375 as the stated inputs, the result is Wall Area = 60 ft^2, Units Needed = 68 units and With Waste Factor = 71 units. Each value corresponds to the declared output fields.
Common Use Cases
- Calculate bricks needed for a garden wall
- Estimate concrete blocks for a garage foundation wall
- Plan materials for a brick fireplace or fire pit