Boyle's Law Calculator

Boyle's Law is evaluated from Initial Pressure, Initial Volume and Final Pressure. The calculation reports Initial Pressure, Initial Volume and Final Pressure.

Results

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About the Boyle's Law Calculator

Boyle's Law is treated here as a quantitative relation between Initial Pressure, Initial Volume, Final Pressure and Final Volume and Initial Pressure, Initial Volume, Final Pressure and Final Volume.

The calculator uses a multi formula configuration. Each reported value is read as a direct evaluation of the stored rules with the declared field formats and units.

Formula basis:
P₁V₁ = P₂V₂ (constant T, constant n)
P₂ = P₁V₁ / V₂
V₂ = P₁V₁ / P₂
P₁ = P₂V₂ / V₁
V₁ = P₂V₂ / P₁

Interpret the outputs in the order shown by the result fields. Optional inputs affect only the outputs that depend on those variables.

Formula & How It Works

The calculation applies the following relations exactly as recorded in the metadata:

P₁V₁ = P₂V₂ (constant T, constant n)
P₂ = P₁V₁ / V₂
V₂ = P₁V₁ / P₂
P₁ = P₂V₂ / V₁
V₁ = P₂V₂ / P₁

Each output field is produced by substituting the supplied inputs into the relevant relation and then applying the declared rounding or text format.

Worked Examples

Example 1: Scuba Diving — Lung Volume at Depth

Inputs

p1: 1 v1: 6 p2: 3
Initial Pressure: 1 atm. Initial Volume: 6 L. Final Pressure: 3 atm. Final Volume: 2 L. Final Pressure: 44.09 psi

With Initial Pressure = 1, Initial Volume = 6 and Final Pressure = 3 as the stated inputs, the result is Initial Pressure = 1 atm, Initial Volume = 6 L and Final Pressure = 3 atm. Each value corresponds to the declared output fields.

Example 2: Bicycle Pump — Compressing Air

Inputs

p1: 1 v1: 1 v2: 0.1
Initial Pressure: 1 atm. Initial Volume: 1 L. Final Pressure: 10 atm. Final Volume: 0.1 L. Final Pressure: 146.96 psi

With Initial Pressure = 1, Initial Volume = 1 and Final Volume = 0.1 as the stated inputs, the result is Initial Pressure = 1 atm, Initial Volume = 1 L and Final Pressure = 10 atm. Each value corresponds to the declared output fields.

Example 3: Medical Syringe Compression

Inputs

p1: 1 v1: 10 v2: 4
Initial Pressure: 1 atm. Initial Volume: 10 L. Final Pressure: 2.5 atm. Final Volume: 4 L. Final Pressure: 36.74 psi

With Initial Pressure = 1, Initial Volume = 10 and Final Volume = 4 as the stated inputs, the result is Initial Pressure = 1 atm, Initial Volume = 10 L and Final Pressure = 2.5 atm. Each value corresponds to the declared output fields.

Example 4: Natural Gas Pipeline Compression

Inputs

p1: 1 v1: 1000 p2: 68
Initial Pressure: 1 atm. Initial Volume: 1,000 L. Final Pressure: 68 atm. Final Volume: 14.7059 L. Final Pressure: 999.32 psi

With Initial Pressure = 1, Initial Volume = 1,000 and Final Pressure = 68 as the stated inputs, the result is Initial Pressure = 1 atm, Initial Volume = 1,000 L and Final Pressure = 68 atm. Each value corresponds to the declared output fields.

Common Use Cases

  • Find final pressure when gas is compressed at constant temperature
  • Calculate new volume after pressure change
  • Understand scuba diving pressure changes